问题
解答题
9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1),其中x=-
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答案
9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1)
=9xy(x2+x-xy-y)-3y(3x2+2xy-3xy-2y2)+6y2(x2+x-xy-y)
=9x3y+9x2y-9x2y2-9xy2-9x2y+3xy2+6y3+6x2y2+6xy2-6xy3-6y3
=9x3y-3x2y2-6xy3,
当x=-
,y=2时,原式=9×(-1 3
)3×2-3×(-1 3
)2×22-6×(-1 3
)×231 3
=-
-2 3
+164 3
=14.