问题 解答题
9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1),其中x=-
1
3
,y=2.
答案

9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1)

=9xy(x2+x-xy-y)-3y(3x2+2xy-3xy-2y2)+6y2(x2+x-xy-y)

=9x3y+9x2y-9x2y2-9xy2-9x2y+3xy2+6y3+6x2y2+6xy2-6xy3-6y3

=9x3y-3x2y2-6xy3

x=-

1
3
,y=2时,原式=9×(-
1
3
3×2-3×(-
1
3
2×22-6×(-
1
3
)×23

=-

2
3
-
4
3
+16

=14.

单项选择题
单项选择题