问题 解答题
当x=2,y=
1
2
时,求代数式(x+y)(x-y)+(x-y)2-(x2-3xy)的值.
答案

(x+y)(x-y)+(x-y)2-(x2-3xy),

=x2-y2+x2-2xy+y2-x2+3xy,

=x2+xy,

当x=2,y=

1
2
时,原式=22+2×
1
2
=5.

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