(1)计算:|-2|+(4-7)÷
(2)先化简,再求值:(3+m)(3-m)+m (m-6)-7,其中m=
(3)解方程:2x2-3x-1=0. |
(1)原式=2-3×
+22 3
=2-2+23
=23
;3
(2)原式=9-m2+m2-6m-7=2-6m,
当m=
时,原式=2×1 2
-6=-5;1 2
(3)∵a=2,b=-3,c=-1,
∴b2-4ac=(-3)2-4×2×(-1)=17,
∴x=
,3± 17 2×2
∴x1=
,x2=-3+ 17 4
.-3- 17 4