问题
选择题
设(5x
|
答案
令x=1得M=4n,又N=2n,
∵M-N=992,∴4n-2n=992,
令2n=k,则k2-k-992=0,
∴k=32,∴n=5,
∵Tr+1=C5r(5x
)5-r(-x1 2
)r1 3
=(-1)r•C5r•55-r•x
,15-r 6
令
=2,得r=3,15-r 6
∴x2项系数为(-1)3C53•52=-250.
故选项为B
设(5x
|
令x=1得M=4n,又N=2n,
∵M-N=992,∴4n-2n=992,
令2n=k,则k2-k-992=0,
∴k=32,∴n=5,
∵Tr+1=C5r(5x
)5-r(-x1 2
)r1 3
=(-1)r•C5r•55-r•x
,15-r 6
令
=2,得r=3,15-r 6
∴x2项系数为(-1)3C53•52=-250.
故选项为B