问题
解答题
化简求值:(x+3y)2+2(x+y)(x-y)-(x-2)(x+3),其中x=2,y=-3.
答案
原式=(x+3y)2+2x2-2y2-x2-x+6
=x2+9y2+6xy+2x2-2y2-x2-x+6
=2x2+7y2+6xy-x+6
当x=2,y=-3时,
原式=2×22+7×(-3)2+6×2×(-3)-2+6
=8+63-36-2+6
=39.
化简求值:(x+3y)2+2(x+y)(x-y)-(x-2)(x+3),其中x=2,y=-3.
原式=(x+3y)2+2x2-2y2-x2-x+6
=x2+9y2+6xy+2x2-2y2-x2-x+6
=2x2+7y2+6xy-x+6
当x=2,y=-3时,
原式=2×22+7×(-3)2+6×2×(-3)-2+6
=8+63-36-2+6
=39.