问题 解答题
若x-y=a,求
1
a2
(x2+y2-ax+ay-2xy-6a2)的值.
答案

1
a2
(x2+y2-ax+ay-2xy-6a2),

=

1
a2
[(x-y)2-a(x-y)-6a2],

=

1
a2
(x-y+2a)(x-y-3a)

∵x-y=a,

∴原式=

1
a2
(a+2a)(a-3a)=
1
a2
×3a×(-2a)=-6.

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