问题
解答题
师徒两个共同加工一批零件,师傅每天加工82个,徒弟每天加工68个,14天完成任务,这批零件共有多少个?(用两种方法解)
答案
方法一,
82×14+68×14
=1148+952,
=2100(个).
答:这批零件共有2128个.
方法二,
(82+68)×14
=150×14,
=2100(个).
答:这批零件共有2128个.
师徒两个共同加工一批零件,师傅每天加工82个,徒弟每天加工68个,14天完成任务,这批零件共有多少个?(用两种方法解)
方法一,
82×14+68×14
=1148+952,
=2100(个).
答:这批零件共有2128个.
方法二,
(82+68)×14
=150×14,
=2100(个).
答:这批零件共有2128个.
阅读理解。 | |||||||||||||||
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