计算
(1)2a b2 (ab-3a2 );
(2)(-2x)2-(2x-2)(2x+1)
(3)2x(2x-3y)-(2x-y)2;
(4)20112-2010×2012(用简便方法计算).
(1)2a b2 (ab-3a2 )
=2a2b3-6a3b2;
(2)(-2x)2-(2x-2)(2x+1)
=4x2-4x2-2x+4x+2
=2x+2;
(3)2x(2x-3y)-(2x-y)2
=4x2-6xy-(4x2-4xy+y2)
=4x2-6xy-4x2+4xy-y2
=-2xy-y2;
(4)20112-2010×2012
=20112-(2011+1)×
=20112-20112+1
=1.