问题 解答题
(1)(-3ab22÷(-2b)3
(2)(3x+1)(2x-1)-2x(
1
2
x-1)

(3)化简,求值:(x+1)2-(x+1)(x-1)+3(1-x)2x=-
1
2
答案

(1)原式=9a2b4÷(-8b3)=-

9
8
a2b;

(2)原式=6x2-3x+2x-1-x2+2x=5x2+x-1;

(3)原式=(x2+2x+1)-(x2-1)+3(x2-2x+1)=x2+2x+1-x2+1+3x2-6x+3=3x2-4x+5,

当x=-

1
2
时,原式=3×(-
1
2
2-4×(-
1
2
)+5=3×
1
4
+2+5=7
3
4

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