问题
解答题
计算: (1)
(2)(x+1)(x+2)(x+3) (3)-(ab3)2•(a4b2)3 (4)(2a-3b+1)(2a+3b-1) (5)562-4×28×47+472. |
答案
(1)原式=4-3+2×
=1+1=2;1 2
(2)原式=(x+1)(x2+5x+6)
=x3+5x2+6x+x2+5x+6
=x3+6x2+11x+6;
(3)原式=-a2b6-a12b6=-a14b12;
(4)原式=[2a-(3b-1)][2a+(3b-1)]
=(2a)2-(3b-1)2
=4a2-9b2+6b-1.
(5)原式=562-2×56×47+472
=(56-47)2
=92
=81.