问题
解答题
先化简,后求值: (1)已知:[(x-2y)2-2y(2y-x)]÷2x,其中x=1,y=2 (2)已知:(2x-1)2-(3x+1)(3x-1)+5x(x-1),其中x=-
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答案
(1)原式=[x2+4y2-4xy-4y2+2xy]÷2x
=(x2-2xy)÷2x
=
,x-2y 2
当x=1,y=2时,原式=
=-1-2×2 2
;3 2
(2)原式=4x2+1-4x-9x2+1+5x2-5x
=2-9x,
当x=-
时,原式=2-9×(-1 3
)=5.1 3