问题 解答题
计算:
(1)(x+y)2n+2÷[
1
2
(x+y)n+1]

(2)(-
3
)2+
(-6)2
-
3-8

(3)(5a2+2a)-4(2+2a2);
(4)5x2(x+1)(x-1).
答案

(1)原式=2(x+y)n+1

(2)原式=3+6-(-2)=3+6+2=11;

(3)原式=(5a2+2a)-(8+8a2)=5a2+2a-8-8a2=-3a2+2a-8;

(4)原式=5x2(x+1)(x-1)=5x2(x2-1)=5x4-5x2

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