问题
解答题
计算: (1)3
(2)(3x-2)2-(2x+4)(2x-4) (3)[8ab2(abc)4-4a3b3c]÷2abc. |
答案
(1)原式=5
+4+(-2)=53
+2;3
(2)原式=9x2-12x+4-4x2+16=5x2-12x+20;
(3)原式=[8a5 b6c4-4a3b3c]÷2abc=4a4b5c3-2a2b2.
计算: (1)3
(2)(3x-2)2-(2x+4)(2x-4) (3)[8ab2(abc)4-4a3b3c]÷2abc. |
(1)原式=5
+4+(-2)=53
+2;3
(2)原式=9x2-12x+4-4x2+16=5x2-12x+20;
(3)原式=[8a5 b6c4-4a3b3c]÷2abc=4a4b5c3-2a2b2.