问题
解答题
(1)计算:
(2)先化简,再求值:[(x+2y)(x-2y)-(x+4y)2]÷4y,其中x=5,y=2. |
答案
(1)原式=-3-0-
+0.5+1 2
=-1 8
;23 8
(2)原式=(x2-4y2-x2-8xy-16y2)÷4y=(-20y2-8xy)÷4y=-4y(5y+2x)÷4y=-(5y+2x)
当x=5,y=2时,原式=-(10+10)=-20.
(1)计算:
(2)先化简,再求值:[(x+2y)(x-2y)-(x+4y)2]÷4y,其中x=5,y=2. |
(1)原式=-3-0-
+0.5+1 2
=-1 8
;23 8
(2)原式=(x2-4y2-x2-8xy-16y2)÷4y=(-20y2-8xy)÷4y=-4y(5y+2x)÷4y=-(5y+2x)
当x=5,y=2时,原式=-(10+10)=-20.