问题
解答题
计算: (1)-
(2)(3a2y2)3÷2(-a3y3)2 (3)x(x2+x+1)-(x+3)(x-4) (4)(x-2y)(x+2y)-(x-2y)2. |
答案
(1)原式=-3-(-1)+15-25=-3+1+15-25=-12;
(2)原式=27(a2)3•(y2)3÷2(-a3)2•(y3)2=27a6y6÷2a6y6=
;27 2
(3)原式=(x3+x2+x)-(x2-4x+3x-12)=x3+x2+x-x2+4x-3x+12=x3+2x+12;
(4)原式=(x2-4y2)-(x2-4xy+4y2)=x2-4y2-x2+4xy-4y2=4xy-8y2.