问题 填空题

计算:[4(a-2)2+12(a+2)(a-2)-8(a-1)2(a-2)]÷4(a-2)=______.

答案

[4(a-2)2+12(a+2)(a-2)-8(a-1)2(a-2)]÷4(a-2),

=[4(a-2)2+12(a+2)(a-2)-8(a-1)2(a-2)]÷4(a-2),

=4(a-2)[(a-2)+3(a+2)-2(a-1)2]÷4(a-2),

=(a-2)+3(a+2)-2(a-1)2

=a-2+3a+6-2+4a-2a2

=-2a2+8a+2.

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