问题
解答题
计算: (1)
(2)
(3)a2(a-1)+(a-5)(a+7); (4)(x-5y)2-(x+5y)2. |
答案
(1)原式=4-2-5=-3;
(2)原式=4-3+3
-3=33
-2;3
(3)原式=a3-a2+a2+7a-5a-35=a3+2a-35;
(4)原式=[(x-5y)+(x+5y)][(x-5y)-(x+5y)]=2x•(-10y)=-20xy.
计算: (1)
(2)
(3)a2(a-1)+(a-5)(a+7); (4)(x-5y)2-(x+5y)2. |
(1)原式=4-2-5=-3;
(2)原式=4-3+3
-3=33
-2;3
(3)原式=a3-a2+a2+7a-5a-35=a3+2a-35;
(4)原式=[(x-5y)+(x+5y)][(x-5y)-(x+5y)]=2x•(-10y)=-20xy.