问题
填空题
若(x+1)5=a0+a1(x-1)+a2(x-1)2+…+a5(x-1)5,则a0=( )
A.1
B.32
C.-1
D.-32
答案
∵(x+1)5=[2+(x-1)]5=
•25+C 05
•24(x-1)+C 15
•23•(x-1)2+C 25
•22(x-1)3+C 35
•2•(X-1)4+C 45
•(x-1)5,C 55
而且 (x+1)5=a0+a1(x-1)+a2(x-1)2+…+a5(x-1)5,
故 a0=
•25=32,C 55
故选B.