问题
解答题
计算: (1)20012-2002×2000 (2)1002-992+982-972+…+22-1 (3)(-2x2)•(-y)+3xy(1-
(4)(2a4+18a3-3a2)÷(-3a2) |
答案
(1)原式=20012-(2001+1)×=20012-(20012-1)=1;
(2)原式=(100+99)(100-99)+(98+87)(98-97)+…+(2+1)(2-1)
=100+99+98+97+…+2+1=5050;
(3)原式=2x2y+3xy-x2y=x2y+3xy;
(4)原式=-
a2-6a+1.2 3