问题
解答题
求下列代数式的值: (1)(3x+2y)(3x-2y)-(x-y)2.其中x=1,y=
(2)[(xy+2)(xy-2)-2(x2y2-2)]÷xy,其中x=10,y=-
|
答案
(1)原式=9x2-4y2-(x2-2xy+y2)
=9x2-4y2-x2+2xy-y2
=8x2+2xy-5y2,
当x=1,y=
时,原式=8×12+2×1×1 2
-5×(1 2
)2=71 2
;3 4
(2)原式=(x2y2-4-2x2y2+4)÷xy
=-x2y2÷xy
=-xy,
当x=10,y=-
时,原式=-10×(-1 25
)=1 25
.2 5