问题
计算题
如图所示。灯L1和L2是并联的,闭合开关,电流表A1的示数是1.2A,电流表A2的示数是0.4A 求:通过灯L1的电流是多少?
答案
解:∵灯L1和灯L2是并联的,干路电流I=1.2A,通过灯L2的电流I2=0.4A,而I=I1+I2 ∴通过灯L1的电流:I1=I-I2=1.2A-0.4A=0.8A。
如图所示。灯L1和L2是并联的,闭合开关,电流表A1的示数是1.2A,电流表A2的示数是0.4A 求:通过灯L1的电流是多少?
解:∵灯L1和灯L2是并联的,干路电流I=1.2A,通过灯L2的电流I2=0.4A,而I=I1+I2 ∴通过灯L1的电流:I1=I-I2=1.2A-0.4A=0.8A。
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