问题
解答题
先化简,再求值,5x2-(3y2+5x2)+(4y2+7xy),其中x=-1,y=1-
|
答案
5x2-(3y2+5x2)+(4y2+7xy),
=5x2-3y2-5x2+4y2+7xy,
=y2+7xy,
当x=-1,y=1-
时2
原式=(1-
)2+7×(-1)×(1-2
)=1-22
+2-7+72
=-4+52
.2
先化简,再求值,5x2-(3y2+5x2)+(4y2+7xy),其中x=-1,y=1-
|
5x2-(3y2+5x2)+(4y2+7xy),
=5x2-3y2-5x2+4y2+7xy,
=y2+7xy,
当x=-1,y=1-
时2
原式=(1-
)2+7×(-1)×(1-2
)=1-22
+2-7+72
=-4+52
.2