问题
填空题
(a+b)[(a+b)2-3ab]-(a-b)[(a-b)2+3ab]=______.
答案
(a+b)[(a+b)2-3ab]-(a-b)[(a-b)2+3ab],
=(a+b)(a2+2ab+b2-3ab)-(a-b)(a2-2ab+b2+3ab),
=(a+b)(a2-ab+b2)-(a-b)(a2+ab+b2),
=a3+b3-a3+b3,
=2b3.
(a+b)[(a+b)2-3ab]-(a-b)[(a-b)2+3ab]=______.
(a+b)[(a+b)2-3ab]-(a-b)[(a-b)2+3ab],
=(a+b)(a2+2ab+b2-3ab)-(a-b)(a2-2ab+b2+3ab),
=(a+b)(a2-ab+b2)-(a-b)(a2+ab+b2),
=a3+b3-a3+b3,
=2b3.