问题 解答题
计算:
(1) (-2)2+(-3)0+3-1
(2)计算:(3x+2)+2(x2-x+2)
(3)(3a5b3-2a4b5)÷(-ab)3
(4)先化简,再求值:(a+b)(a-b)+(a+b)2-2a2,其中a=3,b=-
1
3
答案

(1)原式=4+1+

1
3
=5
1
3

(2)原式=3x+2+2x2-2x+4=2x2+x+6.

(3)原式=

3a5b3-2a4b5
(-ab)3
=
(ab)3(3a2-2ab2)
-(ab)3
=-3a2+2ab2

(4)原式=a2-b2+a2+2ab+b2-2a2=2ab;当a=3,b=-

1
3
时,原式=-2.

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