问题
解答题
求值:(x+2)(x-2)(x2+4)-(x2-2)2,其中x=-
|
答案
原式=(x2-4)(x2+4)-(x4-4x2+4)
=x4-16-x4+4x2-4
=4x2-20
当x=-
时,原式的值=4×(-1 2
)2-20=4×1 2
-20=-19.1 4
求值:(x+2)(x-2)(x2+4)-(x2-2)2,其中x=-
|
原式=(x2-4)(x2+4)-(x4-4x2+4)
=x4-16-x4+4x2-4
=4x2-20
当x=-
时,原式的值=4×(-1 2
)2-20=4×1 2
-20=-19.1 4