问题
解答题
计算:(1)2m2×(-2mn)×(-
(2)(x+3y-2z)(x-2z-3y) |
答案
(1)原式=2m2×(-2mn)×(-
m3n3)×(-m)1 8
=-
m7n4;1 2
(2)原式=[(x-2z)+3y][(x-2z)-3y]
=(x-2z)2-(3y)2
=x2-4xz+4z2-9y2.
计算:(1)2m2×(-2mn)×(-
(2)(x+3y-2z)(x-2z-3y) |
(1)原式=2m2×(-2mn)×(-
m3n3)×(-m)1 8
=-
m7n4;1 2
(2)原式=[(x-2z)+3y][(x-2z)-3y]
=(x-2z)2-(3y)2
=x2-4xz+4z2-9y2.
识读下图:
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A | ![]() |
B | ![]() |
C | ![]() |
D |
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