问题
解答题
(1)
(2)a2-a4+(-a2)3 (3)(x-3y)(x-
(4)(x+1)(x-1)-(x+2)2. |
答案
(1)原式=-2x4y3;
(2)原式=a6-a6=0;
(3)原式=x2-
xy-3xy+1 2
y2=x2-3 2
xy+7 2
y2;3 2
(4)原式=x2-1-(x2+4x+4)=x2-1-x2-4x-4=-4x-5.
(1)
(2)a2-a4+(-a2)3 (3)(x-3y)(x-
(4)(x+1)(x-1)-(x+2)2. |
(1)原式=-2x4y3;
(2)原式=a6-a6=0;
(3)原式=x2-
xy-3xy+1 2
y2=x2-3 2
xy+7 2
y2;3 2
(4)原式=x2-1-(x2+4x+4)=x2-1-x2-4x-4=-4x-5.