问题
解答题
先化简,后求值:[(xy+2)(xy-2)-2x2y2+4]÷(xy),其中x=4,y=-
|
答案
[(xy+2)(xy-2)-2x2y2+4]÷(xy)=[x2y2-4-2x2y2+4]÷(xy)=-x2y2÷(xy)=-xy,
把x=4,y=-
代入上式得:1 4
原式=-4×(-
)=1.1 4
先化简,后求值:[(xy+2)(xy-2)-2x2y2+4]÷(xy),其中x=4,y=-
|
[(xy+2)(xy-2)-2x2y2+4]÷(xy)=[x2y2-4-2x2y2+4]÷(xy)=-x2y2÷(xy)=-xy,
把x=4,y=-
代入上式得:1 4
原式=-4×(-
)=1.1 4