问题
解答题
计算 (1)(
(2)-2(1-
(3)(-2)2012×0.125671. |
答案
(1)(
a2bx)•(-2abx)2 1 2
=(
a2bx)• 4a2b2x21 2
=2a4b3x3 ;
(2)-2(1-
)-4x(2-3x 2
) x-1 4
=-2+3x-8x+x(x-1)
=-2+3x-8x+x2-x
=-2-6x+x2;
(3)(-2)2012×0.125671
=(-2)2012×0.52013
=(-2)2012×0.52012×0.5
=0.5.