问题
解答题
计算题 (1)
(2)(54x2y-108xy2-36xy)÷18xy (3)(2x+3y)(2x-3y)-(2x+3y)2 (4)20052-2006×2004 |
答案
(1)原式=
a2bc3•4a4b4c2=2a6b5c5;1 2
(2)原式=3x-6y-2;
(3)原式=(2x)2-(3y)2-(2x+3y)2,
=4x2-9y2-(4x2+9y2+12xy),
=4x2-9y2-4x2-9y2-12xy,
=-18y2-12xy;
(4)原式=2005×2005-2006×,
=2005×2005-2006×2005+2006,
=2005×+2006,
=1.