问题 解答题
计算题
(1)
1
2
a2bc3-(-2a2b2c)2

(2)(54x2y-108xy2-36xy)÷18xy
(3)(2x+3y)(2x-3y)-(2x+3y)2
(4)20052-2006×2004
答案

(1)原式=

1
2
a2bc3•4a4b4c2=2a6b5c5

(2)原式=3x-6y-2;

(3)原式=(2x)2-(3y)2-(2x+3y)2

=4x2-9y2-(4x2+9y2+12xy),

=4x2-9y2-4x2-9y2-12xy,

=-18y2-12xy;

(4)原式=2005×2005-2006×,

=2005×2005-2006×2005+2006,

=2005×+2006,

=1.

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