问题
解答题
(1)
(2)x2 •(x2)3÷x5 (3)-3xy2z•(x2y)2 (4)(a+b)2-(a-b)2. |
答案
(1)原式=
×6+1 3
×10-1 5
=2+2-5 4
=5 4
;11 4
(2)原式=x2 •x6÷x5=x3;
(3)原式=-3xy2z•x4y2=-3x5y4z;
(4)原式=[(a+b)+(a-b)][(a+b)-(a-b)]=4ab.
(1)
(2)x2 •(x2)3÷x5 (3)-3xy2z•(x2y)2 (4)(a+b)2-(a-b)2. |
(1)原式=
×6+1 3
×10-1 5
=2+2-5 4
=5 4
;11 4
(2)原式=x2 •x6÷x5=x3;
(3)原式=-3xy2z•x4y2=-3x5y4z;
(4)原式=[(a+b)+(a-b)][(a+b)-(a-b)]=4ab.