问题
解答题
计算 (1)(-2a)3+a8÷a6×a (2)(4x-
(3)(x+3)2-(x-3)(x+3) (4)(x+y-1)2 (5)化简求值:[(x-3y)(3x-y)-3y2]÷(2x),其中x=-2,y=
|
答案
(1)原式=-8a3+a2×a
=-8a3+a3
=-7a3;
(2)原式=(4x-
y)(4x+1 2
y),1 2
=16x2-
y2;1 4
(3)原式=x2+6x+9-x2+9
=6x+18;
(4)原式=[(x+y)-1]2
=(x+y)2-2(x+y)+1
=x2+2xy+y2-2x-2y+1;
(5)原式=[3x2-xy-9xy+3y2-3y2]÷(2x)
=[3x2-10xy]÷(2x)
=
x-5y3 2
∵x=-2,y=
. 1 2
∴原式=
×(-2)-5×3 2 1 2
=-3-2.5
=-5.5.