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问题 单项选择题

姐妹俩共养兔100只，姐姐养兔只数的比妹妹养兔只数多16只，问姐姐比妹妹多养多少只（）

A．15

B．20

C．25

D．40

答案

参考答案：B

解析：

由题意可知姐姐养兔的只数是3的倍数，妹妹养兔的只数是10的倍数，总共100只，只可能有三种情况：90与10、60与40、30与70，再考虑姐姐养兔只数的[*]比妹妹养兔只数的[*]多16只，所以姐姐养60只，妹妹养40只，姐姐比妹妹多养60-40=20只。

填空题

质量为1.0kg的物体放在可绕竖直轴转动的水平圆盘上，物体与转轴间用轻弹簧相连。物体与转盘间最大静摩擦力是重力的0.1倍，弹簧的劲度系数为600 N／m，原长为4cm，此时圆盘处于静止状态，如图所示。圆盘开始转动后，要使物体与圆盘保持相对静止，圆盘的最大角速度ω0= _____________；当角速度达到2ω0时，弹簧的伸长量X= _____________。(g取10m／s2)

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单项选择题

The Rational Unified Process (RUP) is a software engineering process, which captures many of best practices in modem software development. The notions of (71) and scenarios have been proven to be an excellent way to capture function requirements. RUP can be described in two dimensions - time and content. In the time dimension, the software lifecycle is broken into cycles. Each cycle is divided into four consecutive (72) which is concluded with a well-defined (73) and can be further broken down into (74) - a complete development loop resulting in a release of an executable product, a subset of the final product under development, which grows incrementally to become the final system. The content structure refers to the disciplines, which group (75) logically by nature.

A. artifactsB. use-cases C. actors D. workers
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