问题
计算题
已知x+y=5,xy=1,
求①x2+y2;
②(x﹣y)2.
答案
解:①x2+y2=(x+y)2﹣2xy,
=52﹣2×1
=25﹣2
=23
②(x﹣y)2=(x+y)2﹣4xy,
=52﹣4×1
=25﹣4
=21
已知x+y=5,xy=1,
求①x2+y2;
②(x﹣y)2.
解:①x2+y2=(x+y)2﹣2xy,
=52﹣2×1
=25﹣2
=23
②(x﹣y)2=(x+y)2﹣4xy,
=52﹣4×1
=25﹣4
=21