问题 计算题

计算:

(1)20092﹣2008×2010;

(2)1022

答案

解:(1)20092﹣2008×2010

=20092﹣(2009﹣1)×(2009+1)

=20092﹣(20092﹣1)

=20092﹣20092+1

=1;

(2)1022

=(100+2)2

=1002+2×100×2+4

=10000+400+4

=10404.

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