问题
填空题
(2+1)(22+1)(24+1)(28+1)…(22048+1)+1的末位数字为______.
答案
(2+1)(22+1)(24+1)(28+1)…(22048+1)+1
=(2-1)(2+1)(22+1)(24+1)(28+1)…(22048+1)+1,
=(22-1)(22+1)(24+1)(28+1)…(22048+1)+1,
=(24-1)(24+1)(28+1)…(22048+1)+1,
=(28-1)(28+1)…(22048+1)+1,
=(216-1)(216+1)…(22048+1)+1,
…
=(22048-1)(22048+1)+1,
=24096-1+1
=24096,
因为24096的末位数字是6,
所以原式末位数字是6.
故答案为:6.