问题
解答题
已知x2-4x+1=0,求x4+
|
答案
∵x2-4x+1=0,
∴x-4+
=0,1 x
即x+
=4,1 x
∴x2+
=(x+1 x2
)2-2,1 x
=42-2,
=14,
∴x4+
=(x2+1 x4
)2-2,1 x2
=142-2,
=194.
故答案为:194.
已知x2-4x+1=0,求x4+
|
∵x2-4x+1=0,
∴x-4+
=0,1 x
即x+
=4,1 x
∴x2+
=(x+1 x2
)2-2,1 x
=42-2,
=14,
∴x4+
=(x2+1 x4
)2-2,1 x2
=142-2,
=194.
故答案为:194.