问题 解答题
x=1
12
41
,y=-
41
53
,求(x+y)2-(x-y)2的值.
答案

解法1:(x+y)2-(x-y)2

=(x2+2xy+y2)-(x2-2xy+y2

=x2+2xy+y2-x2+2xy-y2

=4xy;

解法2:(x+y)2-(x-y)2

=[(x+y)+(x-y)][(x+y)-(x-y)]

=(x+y+x-y)(x+y-x+y)

=2x•2y

=4xy.

x=1

12
41
,y=-
41
53
时,原式=4xy=4×
53
41
×(-
41
53
)=-4.

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