营运驾驶员不仅应当具备相应的职业道德、()、(),了解道路运输法规和业务规范,同时还要掌握一定的车辆技术、故障排除知识。
参考答案:运输服务知识;服务技能
【说明】本程序实现功能:读入两个整数,第1个数除以第2个数,声明当除数为零时抛出异常类DivideByZeroException。public class DivideByZeroException (1) { public DivideByZeroException ( ) { super("Attcmpted to divide by zero"); } }import java.io. *;public class Example { private static int quotient(int numerator, in)\”}t denominator) throws DivideByZeroException {if (denominator==0) throw (2) ;return(numerator / denominator); } public static void main(String args[]) {int number1=0, number2=0, result0;try{ System.out.print1n("Enter the first number:"); number1 = Integer. valueOf(Keyboard.getString()).intValue(); System.out.print1n("Enter the second number:"); number2 = Integer. Va1ueOf(Keyboard.getString()).intValue(); result = quotient(number1,number2);}catch (NumberFormatException e) { System.out.print1n("Invalid integer entered!"); System. exit(-1);}catch ( (3) ) { System.out.print1n(e.to String()); System.exit(-1);}Systcm.out.pfint1n(number1 + "/" + number2 + "=" + result); }}其中, Keyboard类的声明为: import java.io.*; public class Keyboard{ static BufferedReader inputStream = (4) (new InputStreamReader(System.in)); public static int getInteger() {try( return (Intoger.valueOf(inputStream.readLine().trim()).intValue());} catch (Exception e) { e.printStackTrace(); return 0;} } public static String getString() { try{ return (inputStream.readLine()); } catch ( (5) ) { return "0";} }}
病因推断原则中,没有下列哪一条()。
A.联系的强度
B.剂量反应关系
C.对联系进行统计学检验所得P值的大小
D.因果关系的时间顺序
E.研究中病因的量与发病率的量有相关关系