问题 解答题

在球心同侧有相距9cm的两个平行截面,它们的面积分别为49πcm2和400π cm2,求球的表面积.

答案

球的表面积为2 500π cm2

如图,为球的轴截面,

由球的截面性质知,AO1BO2,且O1O2分别为两截面圆的圆心,

OO1AO1,OO2BO2.

设球的半径为R.

π·O2B2=49π,∴O2B=7(cm).

同理πO1A2=400π,∴O1A=20(cm).

OO1=xcm,则OO2=(x+9)cm.

在Rt△OO1A中,R2=x2+202,

在Rt△OO2B中,R2=(x+9)2+72,

x2+202=72+(x+9)2,

解得x=15.

R2=x2+202=252.

R=25(cm).

S=4πR2="2" 500π(cm2).

∴球的表面积为2 500π cm2.

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