问题
填空题
函数f（x）=alnx+x在x=1处取得极值，则a的值为______．
答案
由题意得f′（x）=
+1a x
因为函数f（x）=alnx+x在x=1处取得极值，
所以f′（1）=0，即a+1=0，所以a=-1．
故答案为-1．
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函数f（x）=alnx+x在x=1处取得极值，则a的值为______．
由题意得f′（x）=
+1a x
因为函数f（x）=alnx+x在x=1处取得极值，
所以f′（1）=0，即a+1=0，所以a=-1．
故答案为-1．
| 完型填空。 | |||
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