问题
填空题
(初二)计算(1-
|
答案
(1-
) (1-1 22
)…(1-1 32
) (1-1 20012
)1 20022
=(1+
)(1-1 2
)(1+1 2
)(1-1 3
)…(1+1 3
)(1-1 2001
)(1+1 2001
)(1-1 2002
)1 2002
=
×3 2
×1 2
×4 3
…2 3
×2002 2001
×2000 2001
×2003 2002 2001 2002
=
×1 2 2003 2002
=
.2003 4004
故应填
.2003 4004