问题
解答题
计算: (1)
(2)(2
(3)
|
答案
(1)原式=
+1+33
-13
=4
;3
(2)原式=(2
+33
+22
-33
)(22
+33
-22
+33
)2
=4
×63
=242
;6
(3)原式=2b
•(-ab 3a 2
)•ab a 3 ab
=-a2b
.ab
计算: (1)
(2)(2
(3)
|
(1)原式=
+1+33
-13
=4
;3
(2)原式=(2
+33
+22
-33
)(22
+33
-22
+33
)2
=4
×63
=242
;6
(3)原式=2b
•(-ab 3a 2
)•ab a 3 ab
=-a2b
.ab