问题
填空题
填空:(______)(1+a)=a2-1 x2+x+______=(x+
|
答案
∵a2-1=(a+1)(a-1),
∴a-1)(1+a)=a2-1;
∵(x+
)2=x2+x+1 2
,1 4
∴x2+x+
=(x+1 4
)2.1 2
填空:(______)(1+a)=a2-1 x2+x+______=(x+
|
∵a2-1=(a+1)(a-1),
∴a-1)(1+a)=a2-1;
∵(x+
)2=x2+x+1 2
,1 4
∴x2+x+
=(x+1 4
)2.1 2