问题 解答题
计算:
(1)(2x+1)(-2x+1)
(2)(2a-
1
2
b22
(3)(3x+1)2(3x-1)2
(4)(x+1)(x2+1)(x4+1)(x-1)
答案

(1)(2x+1)(-2x+1),

=12-(2x)2

=1-4x2

(2)(2a-

1
2
b22

=(2a)2-2×2a×

1
2
b2+(
1
2
b2)
2

=4a2-2ab2+

1
4
b4

(3)(3x+1)2(3x-1)2

=[(3x+1)(3x-1)]2

=(9x2-1)2

=81x4-18x2+1;

(4)(x+1)(x2+1)(x4+1)(x-1),

=(x+1)(x-1)(x2+1)(x4+1),

=(x2-1)(x2+1)(x4+1),

=(x4-1)(x4+1),

=x8-1.

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