问题
解答题
乘法公式计算: (1) (-4a-1)(4a-1) (2)(-2x-
(3)(a-
(4) (2a+b+1)(2a+b-1) (5) (a+2b-c)2 |
答案
(1)(-4a-1)(4a-1)=(-1)2-(4a)2=1-16a2;
(2)(-2x-
y)2=4x2+2xy+1 2
y2;1 4
(3)(a-
)2(a+1 2
)2(a2+1 2
)2=[(a-1 4
)(a+1 2
)(a2+1 2
)]2=(a4-1 4
)2=a8-1 16
a4+1 8
;1 256
(4)(2a+b+1)(2a+b-1)=(2a+b)2-12=4a2+4ab+b2-1;
(5)(a+2b-c)2=(a+2b)2-2c(a+2b)+c2=a2+4ab+4b2-2ac-4bc+c2.