问题
解答题
某飞机着陆生滑行的路程s米与时间t秒的关系式为:s=60t-1.5t2,试问飞机着陆后滑行多远才能停止?
答案
∵-1.5<0,
∴函数有最大值.
当t=-
=20时,60 2×(-1.5)
s最大值=
=600,-602 4×(-1.5)
即飞机着陆后滑行600米才能停止.
某飞机着陆生滑行的路程s米与时间t秒的关系式为:s=60t-1.5t2,试问飞机着陆后滑行多远才能停止?
∵-1.5<0,
∴函数有最大值.
当t=-
=20时,60 2×(-1.5)
s最大值=
=600,-602 4×(-1.5)
即飞机着陆后滑行600米才能停止.
阅读理解。 | ||||||||||||||||||||||||||||||||||||||||||||
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