问题 计算题

分解下列因式

(1)(y-1)(y-3)+1

(2)-2x3y+8xy3

答案

(1)解 :(y-1)(y-3) +1 =y2-4y+3+1

=y2-4y+4 =(y-2)2

(2)解 :-2x3y+8xy3 =-2xy(x2-4y2)

=-2xy(x+2y)(x-2y)

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