问题 解答题
求下列函数的导数.
(1)y=2xsin(2x-5);(2)f(x)=ln
x2+1
答案

(1)y'=(2x)'sin(2x-5)+2x[sin(2x-5)]′

=2sin(2x-5)+2x(2x-5)′cos(2x-5)

=2sin(2x-5)+4xcos(2x-5)

(2)f'(x)=

1
x2+1
(
x2+1
)

=

1
x2+1
.
1
2
(x2+1)-
1
2
(x2+1)

=

1
2(x2+1)
.2x

=

x
x2+1

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