求下列函数的导函数 (1)y=x2sinx; (2)y=
|
(1)y′=(x2sinx)′=2xsinx+x2cosx
(2)y′=(
)′=ex+1 ex-1
=(ex+1) ′(ex-1)-(ex+1)(ex-1)′ (ex-1)2 -2ex (ex-1)2
求下列函数的导函数 (1)y=x2sinx; (2)y=
|
(1)y′=(x2sinx)′=2xsinx+x2cosx
(2)y′=(
)′=ex+1 ex-1
=(ex+1) ′(ex-1)-(ex+1)(ex-1)′ (ex-1)2 -2ex (ex-1)2